Optimal. Leaf size=149 \[ \frac{6 d^2 (c+d x) \text{PolyLog}\left (3,-e^{a+b x}\right )}{b^3}-\frac{6 d^2 (c+d x) \text{PolyLog}\left (3,e^{a+b x}\right )}{b^3}-\frac{3 d (c+d x)^2 \text{PolyLog}\left (2,-e^{a+b x}\right )}{b^2}+\frac{3 d (c+d x)^2 \text{PolyLog}\left (2,e^{a+b x}\right )}{b^2}-\frac{6 d^3 \text{PolyLog}\left (4,-e^{a+b x}\right )}{b^4}+\frac{6 d^3 \text{PolyLog}\left (4,e^{a+b x}\right )}{b^4}-\frac{2 (c+d x)^3 \tanh ^{-1}\left (e^{a+b x}\right )}{b} \]
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Rubi [A] time = 0.136457, antiderivative size = 149, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 5, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.357, Rules used = {4182, 2531, 6609, 2282, 6589} \[ \frac{6 d^2 (c+d x) \text{PolyLog}\left (3,-e^{a+b x}\right )}{b^3}-\frac{6 d^2 (c+d x) \text{PolyLog}\left (3,e^{a+b x}\right )}{b^3}-\frac{3 d (c+d x)^2 \text{PolyLog}\left (2,-e^{a+b x}\right )}{b^2}+\frac{3 d (c+d x)^2 \text{PolyLog}\left (2,e^{a+b x}\right )}{b^2}-\frac{6 d^3 \text{PolyLog}\left (4,-e^{a+b x}\right )}{b^4}+\frac{6 d^3 \text{PolyLog}\left (4,e^{a+b x}\right )}{b^4}-\frac{2 (c+d x)^3 \tanh ^{-1}\left (e^{a+b x}\right )}{b} \]
Antiderivative was successfully verified.
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Rule 4182
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int (c+d x)^3 \text{csch}(a+b x) \, dx &=-\frac{2 (c+d x)^3 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{(3 d) \int (c+d x)^2 \log \left (1-e^{a+b x}\right ) \, dx}{b}+\frac{(3 d) \int (c+d x)^2 \log \left (1+e^{a+b x}\right ) \, dx}{b}\\ &=-\frac{2 (c+d x)^3 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{3 d (c+d x)^2 \text{Li}_2\left (-e^{a+b x}\right )}{b^2}+\frac{3 d (c+d x)^2 \text{Li}_2\left (e^{a+b x}\right )}{b^2}+\frac{\left (6 d^2\right ) \int (c+d x) \text{Li}_2\left (-e^{a+b x}\right ) \, dx}{b^2}-\frac{\left (6 d^2\right ) \int (c+d x) \text{Li}_2\left (e^{a+b x}\right ) \, dx}{b^2}\\ &=-\frac{2 (c+d x)^3 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{3 d (c+d x)^2 \text{Li}_2\left (-e^{a+b x}\right )}{b^2}+\frac{3 d (c+d x)^2 \text{Li}_2\left (e^{a+b x}\right )}{b^2}+\frac{6 d^2 (c+d x) \text{Li}_3\left (-e^{a+b x}\right )}{b^3}-\frac{6 d^2 (c+d x) \text{Li}_3\left (e^{a+b x}\right )}{b^3}-\frac{\left (6 d^3\right ) \int \text{Li}_3\left (-e^{a+b x}\right ) \, dx}{b^3}+\frac{\left (6 d^3\right ) \int \text{Li}_3\left (e^{a+b x}\right ) \, dx}{b^3}\\ &=-\frac{2 (c+d x)^3 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{3 d (c+d x)^2 \text{Li}_2\left (-e^{a+b x}\right )}{b^2}+\frac{3 d (c+d x)^2 \text{Li}_2\left (e^{a+b x}\right )}{b^2}+\frac{6 d^2 (c+d x) \text{Li}_3\left (-e^{a+b x}\right )}{b^3}-\frac{6 d^2 (c+d x) \text{Li}_3\left (e^{a+b x}\right )}{b^3}-\frac{\left (6 d^3\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3(-x)}{x} \, dx,x,e^{a+b x}\right )}{b^4}+\frac{\left (6 d^3\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3(x)}{x} \, dx,x,e^{a+b x}\right )}{b^4}\\ &=-\frac{2 (c+d x)^3 \tanh ^{-1}\left (e^{a+b x}\right )}{b}-\frac{3 d (c+d x)^2 \text{Li}_2\left (-e^{a+b x}\right )}{b^2}+\frac{3 d (c+d x)^2 \text{Li}_2\left (e^{a+b x}\right )}{b^2}+\frac{6 d^2 (c+d x) \text{Li}_3\left (-e^{a+b x}\right )}{b^3}-\frac{6 d^2 (c+d x) \text{Li}_3\left (e^{a+b x}\right )}{b^3}-\frac{6 d^3 \text{Li}_4\left (-e^{a+b x}\right )}{b^4}+\frac{6 d^3 \text{Li}_4\left (e^{a+b x}\right )}{b^4}\\ \end{align*}
Mathematica [A] time = 2.94047, size = 191, normalized size = 1.28 \[ \frac{-3 d \left (b^2 (c+d x)^2 \text{PolyLog}(2,-\sinh (a+b x)-\cosh (a+b x))-2 b d (c+d x) \text{PolyLog}(3,-\sinh (a+b x)-\cosh (a+b x))+2 d^2 \text{PolyLog}(4,-\sinh (a+b x)-\cosh (a+b x))\right )+3 d \left (b^2 (c+d x)^2 \text{PolyLog}(2,\sinh (a+b x)+\cosh (a+b x))-2 b d (c+d x) \text{PolyLog}(3,\sinh (a+b x)+\cosh (a+b x))+2 d^2 \text{PolyLog}(4,\sinh (a+b x)+\cosh (a+b x))\right )-2 b^3 (c+d x)^3 \tanh ^{-1}(\sinh (a+b x)+\cosh (a+b x))}{b^4} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.072, size = 541, normalized size = 3.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.50737, size = 450, normalized size = 3.02 \begin{align*} -c^{3}{\left (\frac{\log \left (e^{\left (-b x - a\right )} + 1\right )}{b} - \frac{\log \left (e^{\left (-b x - a\right )} - 1\right )}{b}\right )} - \frac{3 \,{\left (b x \log \left (e^{\left (b x + a\right )} + 1\right ) +{\rm Li}_2\left (-e^{\left (b x + a\right )}\right )\right )} c^{2} d}{b^{2}} + \frac{3 \,{\left (b x \log \left (-e^{\left (b x + a\right )} + 1\right ) +{\rm Li}_2\left (e^{\left (b x + a\right )}\right )\right )} c^{2} d}{b^{2}} - \frac{3 \,{\left (b^{2} x^{2} \log \left (e^{\left (b x + a\right )} + 1\right ) + 2 \, b x{\rm Li}_2\left (-e^{\left (b x + a\right )}\right ) - 2 \,{\rm Li}_{3}(-e^{\left (b x + a\right )})\right )} c d^{2}}{b^{3}} + \frac{3 \,{\left (b^{2} x^{2} \log \left (-e^{\left (b x + a\right )} + 1\right ) + 2 \, b x{\rm Li}_2\left (e^{\left (b x + a\right )}\right ) - 2 \,{\rm Li}_{3}(e^{\left (b x + a\right )})\right )} c d^{2}}{b^{3}} - \frac{{\left (b^{3} x^{3} \log \left (e^{\left (b x + a\right )} + 1\right ) + 3 \, b^{2} x^{2}{\rm Li}_2\left (-e^{\left (b x + a\right )}\right ) - 6 \, b x{\rm Li}_{3}(-e^{\left (b x + a\right )}) + 6 \,{\rm Li}_{4}(-e^{\left (b x + a\right )})\right )} d^{3}}{b^{4}} + \frac{{\left (b^{3} x^{3} \log \left (-e^{\left (b x + a\right )} + 1\right ) + 3 \, b^{2} x^{2}{\rm Li}_2\left (e^{\left (b x + a\right )}\right ) - 6 \, b x{\rm Li}_{3}(e^{\left (b x + a\right )}) + 6 \,{\rm Li}_{4}(e^{\left (b x + a\right )})\right )} d^{3}}{b^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 2.78795, size = 986, normalized size = 6.62 \begin{align*} \frac{6 \, d^{3}{\rm polylog}\left (4, \cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right ) - 6 \, d^{3}{\rm polylog}\left (4, -\cosh \left (b x + a\right ) - \sinh \left (b x + a\right )\right ) + 3 \,{\left (b^{2} d^{3} x^{2} + 2 \, b^{2} c d^{2} x + b^{2} c^{2} d\right )}{\rm Li}_2\left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right ) - 3 \,{\left (b^{2} d^{3} x^{2} + 2 \, b^{2} c d^{2} x + b^{2} c^{2} d\right )}{\rm Li}_2\left (-\cosh \left (b x + a\right ) - \sinh \left (b x + a\right )\right ) -{\left (b^{3} d^{3} x^{3} + 3 \, b^{3} c d^{2} x^{2} + 3 \, b^{3} c^{2} d x + b^{3} c^{3}\right )} \log \left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right ) + 1\right ) +{\left (b^{3} c^{3} - 3 \, a b^{2} c^{2} d + 3 \, a^{2} b c d^{2} - a^{3} d^{3}\right )} \log \left (\cosh \left (b x + a\right ) + \sinh \left (b x + a\right ) - 1\right ) +{\left (b^{3} d^{3} x^{3} + 3 \, b^{3} c d^{2} x^{2} + 3 \, b^{3} c^{2} d x + 3 \, a b^{2} c^{2} d - 3 \, a^{2} b c d^{2} + a^{3} d^{3}\right )} \log \left (-\cosh \left (b x + a\right ) - \sinh \left (b x + a\right ) + 1\right ) - 6 \,{\left (b d^{3} x + b c d^{2}\right )}{\rm polylog}\left (3, \cosh \left (b x + a\right ) + \sinh \left (b x + a\right )\right ) + 6 \,{\left (b d^{3} x + b c d^{2}\right )}{\rm polylog}\left (3, -\cosh \left (b x + a\right ) - \sinh \left (b x + a\right )\right )}{b^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (c + d x\right )^{3} \operatorname{csch}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x + c\right )}^{3} \operatorname{csch}\left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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